# If nC8=nC12 what is the value of n?

A. 5

B. 10

C. 15**D. 20**

**Solution of the Mcq:**

n/ 12 ( n – 12 ) = n / 8 ( n – 8 )

12 = n – 8

n = 12 + 8 = 20

n = 20.

A. 5

B. 10

C. 15**D. 20**

n/ 12 ( n – 12 ) = n / 8 ( n – 8 )

12 = n – 8

n = 12 + 8 = 20

n = 20.

A. 1/3

B. 1/6

C. 1/12**D. 1/36**

A. 1200, 1800, 1600

B. 1000, 1200, 1500**C. 1600, 2400, 1800**D. 800, 1000, 1400

We will take the ratio of all three

Yaser:Hiba:Ali = 8 : 12 : 9

The sum of the ratio is: 29

Now

In order to take out Yaser’s share:

8*5800⁄29 = 1600

Simplified share of Yaser: 1600

Similarly, follow the same procedure for the rest of the two.

A. 70

B. 50

C. 40**D. 60**

Amount of work done by A and B in 1 day = 1/30

Amount of work done by A and B in 20 days = 20 × (1/30) = 20/30 = 2/3

Remaining work – 1 – 2/3 = 1/3

A completes 1/3 work in 20 days

Amount of work A can do in 1 day = (1/3)/20 = 1/60

A can complete the work in 60 days

**A. 12**

B. 15

C. 22

D. 20

Work done by P in 1 day = 1/15

Work done by Q in 1 day = 1/10

Work done by P and Q in 1 day = 1/15 + 1/10 = 1/6

Work done by P and Q in 2 days = 2 × (1/6) = 1/3

Remaining work = 1 – 1/3 = 2/3

Time taken by P to complete the remaining work 2/3 = (2/3) / (1/15) = 10 days

Total time taken = 2 + 10 = 12 days

A. (a-2b)(a^{2}+2b^{2})

B. (a-b)(a+b)(a^{2}-4b^{2})**C. (a ^{2}-2b^{2})(a^{2}+2b^{2})**

D. (a-b)(a+b)(a

A. (a+b)(a^{2}) +ab+b^{2}**B. (a+b)(a ^{2}-ab+b^{2}**

C. (a-b)(a

D. (a-b)(a

**A. log (q/p)**

B. log (p/q) =

C. log (p-q)

D. log (p/q)

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A. 150

B. 160

C. 170**D. 180**

**Explanation:**

(50/100) * X – 30 = 60

0.5*X = 60+ 30, X=90/0.5

X = 180